Gmpy root：TypeError in gmpy2.iroot #257
TypeError in gmpy2.iroot #257
2020年1月18日—Bydefault,gmpy2justmimicsthebehavioroftheunderlyingGMPfunctions.TheGMPfunctionsexpecttheroottobepassasanunsignedlongint ...。其他文章還包含有：「Gmpysqrtprecision」、「gmpy2Documentation」、「gmpy2.iroot」、「Howtocomputethenthrootofaverybiginteger」、「IntegerRoots(GNUMP6.3.0)」、「Integers—gmpy22.2.1documentation」、「Multiple」、「Python」、「SquareandCuberoots.」
查看更多 離開網站
Gmpy sqrt precision
https://stackoverflow.com
The sqrt() function in GMP is only defined for integers. gmpy2 supports the MPFR (floating point) and MPC (complex) libraries in addition to GMP.
gmpy2 Documentation
https://readthedocs.org
isqrt(x, /) → mpz. Return the integer square root of a non-negative integer x. gmpy2.isqrt_rem(x, /). Return a 2-element tuple (s,t) such that ...
gmpy2.iroot
https://wenku.csdn.net
gmpy2.iroot() 函数用于计算一个整数的平方根或其他方根。 函数语法如下： gmpy2.iroot(x, n) 登录后复制. 其中，x为要计算方根的整数，n为方根的 ...
How to compute the nth root of a very big integer
https://stackoverflow.com
I need a way to compute the nth root of a long integer in Python. I tried pow(m, 1.0/n) , but it doesn't work: OverflowError: long int too large ...
Integer Roots (GNU MP 6.3.0)
https://gmplib.org
Root Extraction Functions: Set rop1 to the truncated integer part of the square root of op, like mpz_sqrt. Set rop2 to the remainder op − rop1 * rop1.
Integers — gmpy2 2.2.1 documentation
https://gmpy2.readthedocs.io
gmpy2.iroot(x, n, /) → tuple[mpz, bool] . Return the integer n-th root of x and boolean value that is True iff the root is exact. x >= 0. n > 0. gmpy2.
Multiple
https://gmpy2.readthedocs.io
Return x rounded to the nearest integer by first rounding towards zero and then, if needed, using the current rounding mode. gmpy2.root(x, n, ...
Python
https://lschoe.github.io
inverse exists. iroot(...) iroot(x,n) -> (number, boolean) Return the integer n-th root of x and boolean value that is True iff the root is exact. x >= 0. n ...
Square and Cube roots.
https://python-forum.io
Use int() to ignore the non-integer values: To get a root, use a fraction as an exponent. The square root of 9 is 3. 3 squared is 9. 3**2 is 9. 9**(1/2) is 3.